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.8x^2=200
We move all terms to the left:
.8x^2-(200)=0
a = .8; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·.8·(-200)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*.8}=\frac{0-8\sqrt{10}}{1.6} =-\frac{8\sqrt{10}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*.8}=\frac{0+8\sqrt{10}}{1.6} =\frac{8\sqrt{10}}{1.6} $
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